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Complete Course of Mathematics
Topic 1: Numbers & Numerical Applications Topic 2: Algebra Topic 3: Quantitative Aptitude
Topic 4: Geometry Topic 5: Construction Topic 6: Coordinate Geometry
Topic 7: Mensuration Topic 8: Trigonometry Topic 9: Sets, Relations & Functions
Topic 10: Calculus Topic 11: Mathematical Reasoning Topic 12: Vectors & Three-Dimensional Geometry
Topic 13: Linear Programming Topic 14: Index Numbers & Time-Based Data Topic 15: Financial Mathematics
Topic 16: Statistics & Probability


Content On This Page
Indian System of Numeration International System of Numeration Decimal Number System and Place Value
Formation of Numbers based on Place Value Numbers in General Form Roman Numerals


Numeration Systems and Place Value



Indian System of Numeration


Understanding Numeration Systems

A numeration system is essentially a method or set of rules used to represent or write numbers. Throughout history, various cultures have developed their own ways of representing numbers, such as the Egyptian, Babylonian, Roman, and the widely influential Hindu-Arabic systems.

The system used globally today, including in India, is based on the Hindu-Arabic system. A key feature of this system is its reliance on place value. Place value is the value of a digit based on its position within the number. For example, in the number 222, the digit '2' has different values depending on its place: 2 hundreds, 2 tens, and 2 ones.

To efficiently read and write large numbers using the place value concept, digits are organised into groups called periods. Different conventions exist for this grouping and naming of periods. The two major systems are the Indian System of Numeration and the International System of Numeration.


The Indian System of Numeration

The Indian System of Numeration is a method for grouping and naming digits in large numbers that is widely used in the Indian subcontinent (India, Bangladesh, Pakistan, Nepal, Myanmar, Bhutan, Maldives, Sri Lanka).

In this system, digits are grouped into periods starting from the rightmost digit (the units place). The names of the periods used are specific to the Indian context:

The pattern of grouping digits is unique: the first period from the right (Ones) has three digits, and all subsequent periods (Thousands, Lakhs, Crores, etc.) have two digits. Commas (or sometimes spaces) are used to separate these periods, making the number easier to read by visually chunking the digits.


Place Value Chart in the Indian System

Understanding the place values and periods is essential. The value of each place is ten times the value of the place immediately to its right. The table below shows the place values and their corresponding powers of 10 and number of zeros in the Indian System:

Period $\rightarrow$ Crores Lakhs Thousands Ones
Ten Crores
(TC)
Crores
(C)
Ten Lakhs
(TL)
Lakhs
(L)
Ten Thousands
(TTh)
Thousands
(Th)
Hundreds
(H)
Tens
(T)
Ones
(O)
Value (Powers of 10) $10,00,00,000$
($10^8$)
$1,00,00,000$
($10^7$)
$10,00,000$
($10^6$)
$1,00,000$
($10^5$)
$10,000$
($10^4$)
$1,000$
($10^3$)
$100$
($10^2$)
$10$
($10^1$)
$1$
($10^0$)
Number of Zeros 8 7 6 5 4 3 2 1 0
Position from Right 9th 8th 7th 6th 5th 4th 3rd 2nd 1st

Understanding the relationships between periods is also helpful:

1 Ten = 10 Ones

1 Hundred = 10 Tens = 100 Ones

1 Thousand = 10 Hundreds = 1000 Ones

1 Lakh = 100 Thousands = 100,000 Ones ($10^5$)

1 Crore = 100 Lakhs = 10,000 Thousands = 10,000,000 Ones ($10^7$)

1 Arab = 100 Crores = 1,000,000,000 Ones ($10^9$)

These relationships are based on the powers of 10 system.


Writing and Reading Numbers in the Indian System

To write a number using commas in the Indian System, you start from the rightmost digit and group the digits according to the period structure: the first group has 3 digits, and all subsequent groups have 2 digits. Commas are placed at the end of each period.

To read the number, read the digits in each period together, followed by the name of the period, starting from the leftmost period. The 'Ones' period is read without the word "Ones".

Example 1. Write the number 9876543210 in the Indian System with commas and read it aloud.

Answer:

The given number is 9876543210.

Applying the comma rule from the right:

  • After 3 digits from the right (210): 9876543,210
  • After the next 2 digits (43): 98765,43,210
  • After the next 2 digits (65): 987,65,43,210
  • After the next 2 digits (87): 9,87,65,43,210

The number with commas in the Indian System is:

9,87,65,43,210

[Number with commas - Indian System]

Now, let's read the number by periods from left to right:

  • 9 is in the Arabs period: "Nine Arab"
  • 87 is in the Crores period: "Eighty-seven Crore"
  • 65 is in the Lakhs period: "Sixty-five Lakh"
  • 43 is in the Thousands period: "Forty-three Thousand"
  • 210 is in the Ones period: "Two Hundred Ten"

Putting it all together, the number is read as: Nine Arab Eighty-seven Crore Sixty-five Lakh Forty-three Thousand Two Hundred Ten.


Example 2. Write the number "Five Crore Twelve Lakh Seven Thousand Nine" in numerical form using the Indian System.

Answer:

We need to write the digits for each period and use zeros as placeholders where necessary to ensure each period (except Ones) has two digits and the Ones period has three digits.

  • "Five Crore": The digits in the Crores period are 5. (This is the Ten Crores place and Crores place. Since it's just "Five Crore", it means 5 in the Crores place and 0 in the Ten Crores place, but we read '5 Crore'. Let's write 5 for the Crore place).
  • "Twelve Lakh": The digits in the Lakhs period are 12. (Ten Lakhs place is 1, Lakhs place is 2).
  • "Seven Thousand": The digits in the Thousands period are 7. Since this period requires two places (Ten Thousands and Thousands), and we only have "Seven Thousand", we write 0 in the Ten Thousands place and 7 in the Thousands place. So, the digits are 07.
  • "Nine": The digits in the Ones period are 9. This period requires three places (Hundreds, Tens, Ones). We have 'Nine', which means 9 in the Ones place, and 0 in the Hundreds and Tens places. So, the digits are 009.

Now, combine the digits for each period from left to right, separated by commas:

  • Crores period: 5
  • Lakhs period: 12
  • Thousands period: 07
  • Ones period: 009

Writing these together with commas according to the Indian System (after 3, then 2, 2... digits from the right):

5, 12, 07, 009

[Number in numerical form - Indian System]

The number is 5,12,07,009.


Example 3. Place commas correctly and write the number names for 73456789 in the Indian System.

Answer:

The number is 73456789.

Apply the comma rule from the right:

  • After 3 digits (789): 73456,789
  • After the next 2 digits (56): 73,456,789
  • After the next 2 digits (34): 7,34,56,789

The number with commas is 7,34,56,789.

Now, read the number period by period from left to right:

  • 7 is in the Crores period: "Seven Crore"
  • 34 is in the Lakhs period: "Thirty-four Lakh"
  • 56 is in the Thousands period: "Fifty-six Thousand"
  • 789 is in the Ones period: "Seven Hundred Eighty-nine"

Combining these, the number name is: Seven Crore Thirty-four Lakh Fifty-six Thousand Seven Hundred Eighty-nine.



International System of Numeration


The International System of Numeration

The International System of Numeration is the method used worldwide to read and write large numbers. It is based on the Hindu-Arabic system of place value, but employs a different grouping pattern for periods compared to the Indian System.

In the International System, digits are grouped into periods of three, starting from the rightmost digit (the Units place). Commas (or spaces) are used to separate these periods.

The names of the periods are based on powers of a thousand:

The pattern is consistent: every period consists of three places, following the pattern of "Hundred, Ten, One" of that period name (e.g., Hundred Thousands, Ten Thousands, Thousands).


Place Value Chart in the International System

The table below shows the place values and their corresponding powers of 10 and number of zeros in the International System. Each period, except possibly the leftmost one, has three digits.

Period $\rightarrow$ Millions Thousands Ones
Hundred Millions
(HM)
Ten Millions
(TM)
Millions
(M)
Hundred Thousands
(HTh)
Ten Thousands
(TTh)
Thousands
(Th)
Hundreds
(H)
Tens
(T)
Ones
(O)
Value (Powers of 10) $100,000,000$
($10^8$)
$10,000,000$
($10^7$)
$1,000,000$
($10^6$)
$100,000$
($10^5$)
$10,000$
($10^4$)
$1,000$
($10^3$)
$100$
($10^2$)
$10$
($10^1$)
$1$
($10^0$)
Number of Zeros 8 7 6 5 4 3 2 1 0
Position from Right 9th 8th 7th 6th 5th 4th 3rd 2nd 1st

Just like in the Indian system, the value of each place is ten times the value of the place immediately to its right. The difference is in how these places are grouped into periods.


Writing and Reading Numbers in the International System

To write a number using commas in the International System, you start from the rightmost digit and place commas after every three digits. These commas serve to visually separate the periods (Ones, Thousands, Millions, Billions, etc.).

To read the number, read the digits within each period collectively as a number between 1 and 999, followed by the name of the period, starting from the leftmost period. The 'Ones' period is read as the number itself without the word "Ones".

Example 1. Write the number 9876543210 in the International System with commas and read it aloud.

Answer:

The given number is 9876543210.

Apply the comma rule from the right, grouping digits in threes:

  • After 3 digits (210): 9876543,210
  • After the next 3 digits (543): 9876,543,210
  • After the next 3 digits (876): 9,876,543,210

The number with commas in the International System is:

9,876,543,210

[Number with commas - International System]

Now, let's read the number period by period from left to right. Read the number formed by the digits in each period, followed by the period name:

  • The leftmost period has the digit 9. This is the Billions period: "Nine Billion"
  • The next period has the digits 876. This is the Millions period: "Eight Hundred Seventy-six Million"
  • The next period has the digits 543. This is the Thousands period: "Five Hundred Forty-three Thousand"
  • The rightmost period has the digits 210. This is the Ones period: "Two Hundred Ten"

Putting it all together, the number is read as: Nine Billion Eight Hundred Seventy-six Million Five Hundred Forty-three Thousand Two Hundred Ten.


Example 2. Write the number "Forty-five Million Six Hundred Two Thousand Eighty-one" in numerical form using the International System.

Answer:

Identify the digits for each period, ensuring each period (except the leftmost) has exactly three digits. Use zeros as placeholders where needed.

  • "Forty-five Million": The digits in the Millions period are 45. Since it's the leftmost period, we write 45.
  • "Six Hundred Two Thousand": The digits in the Thousands period are 602. This period needs three digits, and 602 uses three digits.
  • "Eighty-one": The digits in the Ones period are 81. This period needs three digits (Hundreds, Tens, Ones). Eighty-one means 8 in the Tens place and 1 in the Ones place. We need a 0 in the Hundreds place. So, the digits are 081.

Combine the digits for each period from left to right, placing commas after every three digits from the right:

  • Millions period: 45
  • Thousands period: 602
  • Ones period: 081

Writing these together with commas:

45, 602, 081

[Number in numerical form - International System]

The number is 45,602,081.


Example 3. Place commas correctly and write the number names for 73456789 in the International System.

Answer:

The number is 73456789.

Apply the comma rule from the right, grouping digits in threes:

  • After 3 digits (789): 73456,789
  • After the next 3 digits (456): 73,456,789
  • The remaining digits (73) form the leftmost group.

The number with commas is 73,456,789.

Now, read the number period by period from left to right:

  • The leftmost period has the digits 73. This is the Millions period: "Seventy-three Million"
  • The next period has the digits 456. This is the Thousands period: "Four Hundred Fifty-six Thousand"
  • The rightmost period has the digits 789. This is the Ones period: "Seven Hundred Eighty-nine"

Combining these, the number name is: Seventy-three Million Four Hundred Fifty-six Thousand Seven Hundred Eighty-nine.


Comparing the Indian and International Systems

The main difference between the two systems lies in how digits are grouped into periods beyond the Thousands period and the names used for these larger periods. The base unit for grouping in the International system is 1000 (periods of three digits), whereas in the Indian system, after the initial group of 1000, the grouping is based on 100 (periods of two digits).

Place Value Value Grouping and Naming
Indian System International System
Ones$10^0=1$11
Tens$10^1=10$1010
Hundreds$10^2=100$100100
Thousands$10^3=1,000$1,000 (Thousand)1,000 (Thousand)
Ten Thousands$10^4=10,000$10,000 (Ten Thousand)10,000 (Ten Thousand)
Hundred Thousands$10^5=1,00,000$1,00,000 (Lakh)100,000 (Hundred Thousand)
Millions$10^6=10,00,000$10,00,000 (Ten Lakh)1,000,000 (Million)
Ten Millions$10^7=1,00,00,000$1,00,00,000 (Crore)10,000,000 (Ten Million)
Hundred Millions$10^8=10,00,00,000$10,00,00,000 (Ten Crore)100,000,000 (Hundred Million)
Billions$10^9=1,00,00,00,000$1,00,00,00,000 (Arab)1,000,000,000 (Billion)
Ten Billions$10^{10}=10,00,00,00,000$10,00,00,00,000 (Ten Arab)10,000,000,000 (Ten Billion)
Hundred Billions$10^{11}=1,00,00,00,00,000$1,00,00,00,00,000 (Kharab)100,000,000,000 (Hundred Billion)
Trillions$10^{12}=10,00,00,00,00,000$10,00,00,00,00,000 (Ten Kharab)1,000,000,000,000 (Trillion)

This table highlights the differences in period names and comma placement for larger numbers. The common equivalences between the two systems are important for conversions:

1 Lakh = 100 Thousand

1 Crore = 100 Lakh = 10 Million

1 Arab = 100 Crore = 1 Billion



Decimal Number System and Place Value


The Decimal Number System (Base-10)

The Decimal Number System, also known as the base-10 system, is the most commonly used number system for representing both whole numbers and numbers with fractional parts. It is a positional notation system, meaning the value of a digit is determined not only by the digit itself but also by its position within the number.

The decimal system uses a set of ten unique digits: $0, 1, 2, 3, 4, 5, 6, 7, 8,$ and $9$. These ten digits are used in combination to represent any number, regardless of its magnitude or whether it has a fractional component.

The power of the decimal system comes from its use of place value. The value contributed by each digit to the overall number is the product of the digit's face value and the value of its position (place).


Place Value for Whole Numbers

In a whole number, the place values are powers of 10 that increase as you move from right to left, starting from the digit immediately to the left of the decimal point (which is implicitly present even in whole numbers).

The fundamental principle is that the place value of any digit is exactly ten times the place value of the digit to its immediate right. This makes calculations and understanding the magnitude of numbers very efficient.


Place Value for Decimal Numbers (Fractional Part)

Numbers with fractional parts are represented using a decimal point (.). The decimal point separates the whole number part (to the left) from the fractional or decimal part (to the right).

The places to the right of the decimal point represent values less than one. Their place values are powers of 10 that decrease as you move away from the decimal point to the right.

Each place value to the right of the decimal point is one-tenth ($\frac{1}{10}$) of the value of the place immediately to its left. This consistent pattern across the decimal point allows for the seamless representation of numbers with both integer and fractional parts.

The structure of place values centered around the decimal point is:

... $10^3$ (Thousands), $10^2$ (Hundreds), $10^1$ (Tens), $10^0$ (Ones) . $10^{-1}$ (Tenths), $10^{-2}$ (Hundredths), $10^{-3}$ (Thousandths) ...


Expanded Form of a Number

The expanded form of a number is a way of writing it as the sum of the values of each of its digits. This explicitly shows how place value works. Each term in the sum is the product of a digit and its corresponding place value (expressed as a power of 10 or its numerical value).

Example 1. Write the number 7,45,903 in expanded form using powers of 10.

Answer:

The given number is 7,45,903. We identify the digit at each place value (using the Indian System place names as in the number format):

  • The digit 7 is in the Lakhs place, value $1,00,000 = 10^5$.
  • The digit 4 is in the Ten Thousands place, value $10,000 = 10^4$.
  • The digit 5 is in the Thousands place, value $1,000 = 10^3$.
  • The digit 9 is in the Hundreds place, value $100 = 10^2$.
  • The digit 0 is in the Tens place, value $10 = 10^1$.
  • The digit 3 is in the Ones place, value $1 = 10^0$.

The expanded form is the sum of (digit $\times$ place value) for each digit:

7,45,903 = $(7 \times 1,00,000) + (4 \times 10,000) + (5 \times 1,000) + (9 \times 100) + (0 \times 10) + (3 \times 1)$

Using powers of 10:

7,45,903 = $(7 \times 10^5) + (4 \times 10^4) + (5 \times 10^3) + (9 \times 10^2) + (0 \times 10^1) + (3 \times 10^0)$

Including terms with a digit of 0 in the expanded form using powers of 10 helps to clearly show the contribution of each place value, even if that contribution is zero.


Example 2. Write the number 87.605 in expanded form using powers of 10.

Answer:

The given number is 87.605. Identify the place value for each digit:

  • The digit 8 is in the Tens place (to the left of the decimal), value $10^1$.
  • The digit 7 is in the Ones place (to the left of the decimal), value $10^0$.
  • The digit 6 is in the Tenths place (to the right of the decimal), value $10^{-1}$.
  • The digit 0 is in the Hundredths place (to the right of the decimal), value $10^{-2}$.
  • The digit 5 is in the Thousandths place (to the right of the decimal), value $10^{-3}$.

Write the sum of the product of each digit and its place value:

87.605 = $(8 \times 10) + (7 \times 1) + (6 \times 0.1) + (0 \times 0.01) + (5 \times 0.001)$

Using powers of 10:

87.605 = $(8 \times 10^1) + (7 \times 10^0) + (6 \times 10^{-1}) + (0 \times 10^{-2}) + (5 \times 10^{-3})$


Face Value vs. Place Value

It is crucial to distinguish between the **face value** and the **place value** (or positional value) of a digit within a number. While the face value is inherent to the digit symbol, the place value depends on its position.

Example 3. In the number 65,30,148, find the face value and place value of the digit 5.

Answer:

The given number is 65,30,148. The digit under consideration is 5.

Face Value:

The face value of the digit 5 is simply 5.

Place Value:

First, identify the position of the digit 5 in the number 65,30,148. Using the Indian System (as indicated by the commas):

The places from right to left are: Ones, Tens, Hundreds, Thousands, Ten Thousands, Lakhs, Ten Lakhs, Crores.

The digit 5 is in the Lakhs place.

The value of the Lakhs place is $1,00,000$ (or $10^5$).

Now, calculate the place value:

Place Value of 5 = Face Value of 5 $\times$ Value of Lakhs place

Place Value of 5 = $5 \times 1,00,000$

Place Value of 5 = 5,00,000

So, in the number 65,30,148, the face value of the digit 5 is 5, and its place value is 5,00,000.


Example 4. In the number 4.079, find the place value of the digit 7.

Answer:

The given number is 4.079. The digit under consideration is 7.

Identify the position of the digit 7. It is to the right of the decimal point.

The places to the right of the decimal point are: Tenths, Hundredths, Thousandths.

The digit 0 is in the Tenths place ($10^{-1}$).

The digit 7 is in the Hundredths place ($10^{-2}$).

The value of the Hundredths place is $0.01$ (or $10^{-2}$).

Now, calculate the place value:

Place Value of 7 = Face Value of 7 $\times$ Value of Hundredths place

Place Value of 7 = $7 \times 0.01$

Place Value of 7 = 0.07

So, in the number 4.079, the place value of the digit 7 is 0.07.



Formation of Numbers based on Place Value

Understanding the concept of place value is crucial not only for reading and interpreting numbers but also for constructing numbers based on given information about their digits and positions. We can form a number if we know the value of each digit at its respective place or if the number is given in its expanded form.


Forming Numbers from Place Values or Expanded Form

When you are given the digits along with their corresponding place values, or the number is presented in expanded form, you can reconstruct the standard numerical representation of the number. The key is to correctly identify the digit belonging to each place value and arrange them in the standard order, from the highest place value on the left to the lowest place value on the right.

If a particular place value is not mentioned in the description or expanded form, it means the digit at that position is 0. It is important to include these zeros as placeholders to ensure the digits are in their correct positions.

Example 1. Write the number for the following expanded form: $(9 \times 10^5) + (2 \times 10^4) + (0 \times 10^3) + (7 \times 10^2) + (5 \times 10^1) + (1 \times 10^0)$.

Answer:

The expanded form shows the contribution of each digit based on its place value (represented as a power of 10). We can directly identify the digit corresponding to each power of 10:

  • The term with $10^5$ is $(9 \times 10^5)$. This means the digit in the $10^5$ (Lakhs or Hundred Thousands) place is 9.
  • The term with $10^4$ is $(2 \times 10^4)$. The digit in the $10^4$ (Ten Thousands) place is 2.
  • The term with $10^3$ is $(0 \times 10^3)$. The digit in the $10^3$ (Thousands) place is 0.
  • The term with $10^2$ is $(7 \times 10^2)$. The digit in the $10^2$ (Hundreds) place is 7.
  • The term with $10^1$ is $(5 \times 10^1)$. The digit in the $10^1$ (Tens) place is 5.
  • The term with $10^0$ is $(1 \times 10^0)$. The digit in the $10^0$ (Ones) place is 1.

Now, arrange these digits according to the decreasing powers of 10 (which corresponds to place values from left to right):

Place values: $10^5, 10^4, 10^3, 10^2, 10^1, 10^0$

Digits: $\quad \quad \quad 9, \quad 2, \quad 0, \quad 7, \quad 5, \quad 1$

Writing these digits in sequence gives the number 920751.

We can also calculate the value of each term and sum them:

$(9 \times 100000) + (2 \times 10000) + (0 \times 1000) + (7 \times 100) + (5 \times 10) + (1 \times 1)$

$= 900000 + 20000 + 0 + 700 + 50 + 1$

$= 920751$

The number is 920751. Using commas (Indian System): 9,20,751. Using commas (International System): 920,751.


Example 2. Form the number that has 3 in the Crores place, 8 in the Lakhs place, 1 in the Ten Thousands place, 5 in the Hundreds place, and 4 in the Ones place. Assume all other places are 0.

Answer:

We are given the digits for specific place values in the Indian System. We need to determine the digits for all place values from the highest mentioned down to the Ones place, using 0 for any unmentioned places.

Let's list the relevant place values from highest to lowest (using the Indian System as indicated):

  • Ten Crores ($10^8$)
  • Crores ($10^7$)
  • Ten Lakhs ($10^6$)
  • Lakhs ($10^5$)
  • Ten Thousands ($10^4$)
  • Thousands ($10^3$)
  • Hundreds ($10^2$)
  • Tens ($10^1$)
  • Ones ($10^0$)

Now, fill in the digit for each place based on the information provided and the assumption that unmentioned places have a digit of 0:

  • Ten Crores: Not mentioned, so digit is 0.
  • Crores: Given as 3.
  • Ten Lakhs: Not mentioned, so digit is 0.
  • Lakhs: Given as 8.
  • Ten Thousands: Given as 1.
  • Thousands: Not mentioned, so digit is 0.
  • Hundreds: Given as 5.
  • Tens: Not mentioned, so digit is 0.
  • Ones: Given as 4.

Arrange the digits in order from Ten Crores down to Ones:

Digits: 0, 3, 0, 8, 1, 0, 5, 0, 4

Since the leftmost digit is 0, and it's not the only digit in the number, this 0 is usually omitted when writing the number in standard form (unless specified to include all digits up to the highest place value). The number starts from the first non-zero digit from the left, which is 3.

The digits are 3, 0, 8, 1, 0, 5, 0, 4.

Write this number using commas in the Indian System:

3,08,10,504

[Number in numerical form - Indian System]

The number formed is 3,08,10,504. (In International System: 30,810,504).


Comparing Numbers Using Place Value

The place value system provides a systematic and efficient method for comparing the magnitude of two numbers, regardless of how large they are.

  1. Compare the number of digits: For two non-negative integers, the number with more digits is larger. For example, 1,000 (4 digits) is larger than 999 (3 digits).
  2. If the number of digits is the same: Start comparing the digits from the leftmost position (the highest place value) moving towards the right (to lower place values).
  3. Compare digits at each place: At the first place where the digits of the two numbers are different, the number with the larger digit at that position is the greater number.
  4. If all digits are the same: If the numbers have the same number of digits and all corresponding digits are identical, the numbers are equal.

Example 3. Compare 9,87,65,432 and 98,76,54,320 using place value.

Answer:

The first number is 9,87,65,432.

Let's count the number of digits: There are 8 digits.

The second number is 98,76,54,320.

Let's count the number of digits: There are 10 digits.

Since the second number (98,76,54,320) has more digits (10) than the first number (9,87,65,432) which has 8 digits, the second number is larger.

Therefore, 9,87,65,432 < 98,76,54,320.

Let's consider an example where the number of digits is the same.


Example 4. Compare 5,67,890 and 5,67,980 using place value.

Answer:

Both numbers have 6 digits. We will compare the digits starting from the leftmost place (the highest place value).

Numbers: 5,67,890 and 5,67,980

Place Values (from left to right in Indian System): Lakhs, Ten Thousands, Thousands, Hundreds, Tens, Ones.

  • Lakhs place: The digit is 5 in both numbers. (They are equal at this place).
  • Ten Thousands place: The digit is 6 in both numbers. (They are equal at this place).
  • Thousands place: The digit is 7 in both numbers. (They are equal at this place).
  • Hundreds place: The digit in the first number is 8. The digit in the second number is 9.

    Comparing these digits: $8 < 9$

Since the digits differ first at the Hundreds place, and the second number has a larger digit (9) at this place compared to the first number (8), the second number is larger.

Therefore, 5,67,890 < 5,67,980.


Forming the Smallest/Largest Number from Given Digits

Place value is also used to determine how to arrange a given set of digits to form the smallest or largest possible number with those digits. This assumes each digit is used exactly once and we are forming integers.

Example 5. Write the smallest and largest 6-digit numbers using the digits 5, 2, 0, 8, 1, 7 without repetition.

Answer:

The given digits are 5, 2, 0, 8, 1, and 7. There are 6 digits.

Largest 6-digit number:

Arrange the digits in descending order:

8, 7, 5, 2, 1, 0

Place them in the positions from left to right (Ten Lakhs to Ones):

The largest number is 875210.

Smallest 6-digit number:

Arrange the digits in ascending order:

0, 1, 2, 5, 7, 8

If we simply write them in this order (012578), this is the number 12578, which is a 5-digit number. To form the smallest 6-digit number, the first digit must be the smallest non-zero digit.

The smallest non-zero digit is 1. Place 1 at the leftmost position.

Place the digit 0 immediately after the first digit.

Arrange the remaining digits (2, 5, 7, 8) in ascending order and place them after 0.

Arrangement: 1 (smallest non-zero), then 0, then 2, 5, 7, 8.

The smallest number is 102578.


Example 6. Write the smallest and largest 4-digit numbers using the digits 3, 9, 3, 0 with repetition allowed.

Answer:

The given digits are 3, 9, 3, 0. We need to form 4-digit numbers with repetition allowed.

Largest 4-digit number:

To make the number largest, we want the largest digit in the highest place value (Thousands place), then the next largest in the Hundreds place, and so on. Since repetition is allowed, we can use the largest digit (9) in all places.

Largest number: 9999.

Smallest 4-digit number:

To make the number smallest, we want the smallest digit in the highest place value (Thousands place). However, we cannot place 0 in the Thousands place as it would result in a 3-digit number. The smallest non-zero digit available is 3. So, place 3 in the Thousands place.

For the remaining places (Hundreds, Tens, Ones), we want the smallest possible digits. Since repetition is allowed and 0 is the smallest digit, we place 0 in the remaining three places.

Smallest number: 3000.



Numbers in General Form


General Form of Numbers using Variables

The general form of a number is an algebraic representation that expresses the number in terms of its digits and their respective place values. Using variables to represent the digits is a powerful technique in number theory as it allows us to describe properties that hold for any number of a specific structure (like any two-digit number or any three-digit number) and to prove interesting relationships between numbers and their digits.


1. General Form of a Two-Digit Number

Consider a two-digit number. Let the digit in the tens place be $a$ and the digit in the ones place be $b$.

In a two-digit number, the tens digit ($a$) cannot be zero (otherwise, it would be a one-digit number). So, $a$ must be an integer such that $1 \le a \le 9$. The ones digit ($b$) can be any integer from 0 to 9, i.e., $0 \le b \le 9$.

Using place value, the value contributed by the tens digit is $a \times 10$.

The value contributed by the ones digit is $b \times 1$.

The number is the sum of these values:

Number = $(a \times 10) + (b \times 1)$

Thus, the general form of a two-digit number with digits $a$ and $b$ (where $a$ is the tens digit and $b$ is the ones digit) is:

Number = $10a + b$

[General form of a 2-digit number $ab$]

Example: The number 57 has the tens digit $a=5$ and the ones digit $b=7$. Its general form representation is $10(5) + 7 = 50 + 7 = 57$.

If we reverse the digits of this number, the new tens digit becomes $b$ and the new ones digit becomes $a$. The general form of the number with reversed digits is $10b + a$. For the number 57, the reversed number is 75, and its general form is $10(7) + 5 = 70 + 5 = 75$.


2. General Form of a Three-Digit Number

Consider a three-digit number. Let the digits from left to right be $a, b,$ and $c$. Here, $a$ is the hundreds digit, $b$ is the tens digit, and $c$ is the ones digit.

For it to be a three-digit number, the hundreds digit ($a$) must be non-zero ($1 \le a \le 9$). The digits $b$ and $c$ can be any integer from 0 to 9 ($0 \le b \le 9, 0 \le c \le 9$).

Using place value:

Value of hundreds digit = $a \times 100$

Value of tens digit = $b \times 10$

Value of ones digit = $c \times 1$

The number is the sum of these values:

Number = $(a \times 100) + (b \times 10) + (c \times 1)$

Thus, the general form of a three-digit number with digits $a, b, c$ from hundreds to ones place is:

Number = $100a + 10b + c$}

[General form of a 3-digit number $abc$]

Example: The number 285 has $a=2, b=8, c=5$. Its general form is $100(2) + 10(8) + 5 = 200 + 80 + 5 = 285$.

Using the same digits $a, b, c$, other three-digit numbers can be formed by permuting the digits (if they are distinct and none are zero, or if placing a zero does not reduce the number of digits). For example, the number formed by digits $a, c, b$ in the hundreds, tens, ones places respectively would be $100a + 10c + b$. The number formed by digits $b, a, c$ would be $100b + 10a + c$ (assuming $b \neq 0$).


3. General Form of an n-Digit Number

This concept can be extended to any number of digits. Consider an $n$-digit number with digits $d_{n-1}, d_{n-2}, ..., d_1, d_0$ arranged from left to right. Here, $d_{n-1}$ is the digit in the highest place value ($10^{n-1}$), $d_{n-2}$ is in the place value $10^{n-2}$, and so on, until $d_0$ in the ones place ($10^0$).

For it to be an $n$-digit number, the leftmost digit $d_{n-1}$ must be non-zero ($1 \le d_{n-1} \le 9$). All other digits $d_i$ for $0 \le i < n-1$ can be any integer from 0 to 9 ($0 \le d_i \le 9$).

The general form of this $n$-digit number is the sum of each digit multiplied by its corresponding place value (power of 10):

Number = $(d_{n-1} \times 10^{n-1}) + (d_{n-2} \times 10^{n-2}) + ... + (d_1 \times 10^1) + (d_0 \times 10^0)$

This can be expressed more compactly using summation notation:

Number = $\sum\limits_{i=0}^{n-1} d_i \times 10^i$

[General form using summation]

Example: The 4-digit number 6149 has $n=4$. The digits are $d_3=6, d_2=1, d_1=4, d_0=9$.

General form: $(6 \times 10^3) + (1 \times 10^2) + (4 \times 10^1) + (9 \times 10^0) = 6000 + 100 + 40 + 9 = 6149$.


Using General Form to Prove Number Properties

The general form of numbers is a powerful tool for proving various properties related to divisibility, relationships between numbers and their reversed digits, and other number puzzles. By working with the algebraic representation, the properties become clear and can be generalized.

Example 1. Prove that the difference between a two-digit number and the number obtained by reversing its digits is always divisible by 9.

Proof:

Given: A two-digit number.

To Prove: The difference between the number and the number formed by reversing its digits is divisible by 9.

Proof:

Let the two-digit number be represented by its digits $a$ and $b$, where $a$ is the tens digit ($1 \le a \le 9, a \in \mathbb{Z}$) and $b$ is the ones digit ($0 \le b \le 9, b \in \mathbb{Z}$).

The general form of the original number is $10a + b$.

The number obtained by reversing the digits has $b$ as the tens digit and $a$ as the ones digit. Its general form is $10b + a$.

We need to find the difference between these two numbers. Let's subtract the reversed number from the original number:

Difference = $(10a + b) - (10b + a)$

Remove the parentheses. Remember to distribute the negative sign to both terms inside the second set of parentheses:

Difference = $10a + b - 10b - a$

Group the terms with the same variables ($a$ terms and $b$ terms):

Difference = $(10a - a) + (b - 10b)$

Perform the subtractions within each group:

Difference = $9a + (-9b)$

Difference = $9a - 9b$

Factor out the common factor, which is 9:

Difference = $9(a - b)$

Since $a$ and $b$ are integers, their difference $(a - b)$ is also an integer. Any number that can be written in the form $9 \times (\text{an integer})$ is divisible by 9.

Therefore, the difference between a two-digit number and the number obtained by reversing its digits is always divisible by 9.

Note: If the reversed number is larger, the difference would be $(10b+a) - (10a+b) = 9b - 9a = 9(b-a)$. This is also a multiple of 9, just potentially negative. Divisibility by 9 means the difference is a multiple of 9 (positive or negative).


Example 2. Prove that the sum of a three-digit number $abc$ and the numbers $bca$ and $cab$ (formed by cyclically shifting the digits) is always divisible by 111.

Proof:

Given: A three-digit number with digits $a, b, c$, where $a$ is the hundreds digit ($1 \le a \le 9, a \in \mathbb{Z}$) and $b, c$ are the tens and ones digits respectively ($0 \le b, c \le 9, b, c \in \mathbb{Z}$).

To Prove: The sum of the numbers $abc, bca,$ and $cab$ is divisible by 111.

Proof:

Let the original three-digit number $abc$ be represented in its general form $N_1 = 100a + 10b + c$.

The number $bca$ is formed by taking the tens digit ($b$) as the new hundreds digit, the ones digit ($c$) as the new tens digit, and the hundreds digit ($a$) as the new ones digit. Its general form is $N_2 = 100b + 10c + a$. (Note: This assumes $b \neq 0$. If $b=0$, $bca$ would be a two-digit number $ca$. The property still holds, but the representation changes slightly. The proof below using general forms works regardless of whether $b$ or $c$ are zero, as long as the initial number $abc$ is a 3-digit number, meaning $a \neq 0$).

The number $cab$ is formed by taking the ones digit ($c$) as the new hundreds digit, the hundreds digit ($a$) as the new tens digit, and the tens digit ($b$) as the new ones digit. Its general form is $N_3 = 100c + 10a + b$. (Note: This assumes $c \neq 0$).

We need to find the sum of these three general forms: $N_1 + N_2 + N_3$.

Sum = $(100a + 10b + c) + (100b + 10c + a) + (100c + 10a + b)$

Group the terms involving $a$, $b$, and $c$ separately:

Sum = $(100a + a + 10a) + (10b + 100b + b) + (c + 10c + 100c)$

Combine the coefficients for each variable:

Sum = $111a + 111b + 111c$}

Factor out the common factor, which is 111:

Sum = $111(a + b + c)$

Since $a, b,$ and $c$ are the digits of the number, they are integers. The sum of integers $(a + b + c)$ is also an integer. Therefore, $111(a + b + c)$ is always a multiple of 111.

This shows that the sum of a three-digit number $abc$ and the numbers formed by cyclically shifting its digits ($bca$ and $cab$) is always divisible by 111.


Example 3. Prove that the difference between a three-digit number $abc$ and the number $cba$ (formed by reversing the digits) is always divisible by 99.

Proof:

Given: A three-digit number $abc$.

To Prove: The difference between $abc$ and $cba$ is divisible by 99.

Proof:

Let the three-digit number be $abc$. Its general form is $100a + 10b + c$, where $1 \le a \le 9$ and $0 \le b, c \le 9$.

The number formed by reversing the digits is $cba$. Its general form is $100c + 10b + a$. (Note: For $cba$ to be a 3-digit number, $c$ must be non-zero, i.e., $1 \le c \le 9$. However, the property holds even if $c=0$, provided $a \neq 0$ and the original number is treated as a 3-digit number with a zero in the ones place). The proof below works for the difference in values.

Let's find the difference between the number $abc$ and the number $cba$. We can consider $|(100a + 10b + c) - (100c + 10b + a)|$ to cover both cases where $abc > cba$ or $cba > abc$. Or simply compute one difference and note the divisibility property applies to the result.

Difference = $(100a + 10b + c) - (100c + 10b + a)$

Remove parentheses:

Difference = $100a + 10b + c - 100c - 10b - a$

Group like terms:

Difference = $(100a - a) + (10b - 10b) + (c - 100c)$

Combine like terms:

Difference = $99a + 0b + (-99c)$

Difference = $99a - 99c$

Factor out 99:

Difference = $99(a - c)$

Since $a$ and $c$ are digits (integers), their difference $(a - c)$ is also an integer. Therefore, $99(a - c)$ is always a multiple of 99.

This proves that the difference between a three-digit number $abc$ and the number $cba$ is always divisible by 99.



Roman Numerals


The Roman Numeral System

The Roman numeral system is an ancient system of numerical notation that originated in Rome. It uses a combination of seven basic symbols (capital letters) to represent numbers. Unlike the decimal (Hindu-Arabic) system which is positional and based on powers of 10, the Roman system is primarily additive and subtractive.

The seven basic symbols and their corresponding values are:

Symbol Value
I1
V5
X10
L50
C100
D500
M1000

A significant feature of the traditional Roman numeral system is the absence of a symbol for zero. This, along with its non-positional nature (except for the subtractive rule), made complex arithmetic calculations difficult compared to modern systems.


Rules for Forming Roman Numerals

Numbers in the Roman system are formed by combining the basic symbols according to specific rules:

Rule 1: Repetition of Symbols (Additive Principle)

Symbols I, X, C, and M can be repeated consecutively, typically up to three times. When repeated, their values are added.

The symbols V, L, and D are never repeated. For example, VV for 10 is incorrect; X is used instead. LL for 100 is incorrect; C is used. DD for 1000 is incorrect; M is used.

Modern usage often restricts repetition of I, X, C, M to at most three times. For four, the subtractive rule is usually preferred (e.g., IV instead of IIII, XL instead of XXXX, etc.).

Rule 2: Addition (Larger Symbol Followed by Smaller Symbol)

If a symbol of smaller value is placed to the right of a symbol of larger value, the value of the smaller symbol is added to the value of the larger symbol.

This rule is applied sequentially. Read from left to right, adding values unless the subtractive rule applies.

Examples:

Rule 3: Subtraction (Smaller Symbol Preceding Larger Symbol)

If a symbol of smaller value is placed immediately to the left of a symbol of larger value, the value of the smaller symbol is subtracted from the value of the larger symbol. This rule is used to represent numbers that are one less than certain values (like 4, 9, 40, 90, 400, 900) and to avoid excessive repetition of symbols (like using IV instead of IIII).

There are specific rules for which symbols can be subtracted and from which larger symbols:

Examples:

To read a Roman numeral, look for these subtractive combinations first, calculate their value, and then apply the additive rule for the rest.

Rule 4: The Bar (Vinculum)

To represent very large numbers, a horizontal line (called a bar or vinculum) is placed over a Roman numeral. This bar indicates that the value of the numeral is multiplied by 1000.

If a number combines symbols with a bar and symbols without a bar, first calculate the value of the barred part (including any additive/subtractive combinations under the bar) and multiply by 1000, then add the value of the remaining symbols.

Examples:


Converting Between Hindu-Arabic and Roman Numerals

Converting from Hindu-Arabic to Roman Numerals

To convert a number from our standard decimal (Hindu-Arabic) system to Roman numerals, the easiest method is to break down the number according to its place values (Thousands, Hundreds, Tens, Ones) and convert each component separately into its Roman numeral equivalent, keeping the subtraction rule in mind. Then combine these Roman numerals in order from the largest value component to the smallest.

Example 1. Convert 1947 to Roman numerals.

Answer:

Break down the number 1947 by place value:

  • Thousands place: 1000 = M
  • Hundreds place: 900 = 1000 - 100 = CM
  • Tens place: 40 = 50 - 10 = XL
  • Ones place: 7 = 5 + 1 + 1 = VII

Combine the Roman numerals for each component in order:

1947 = 1000 + 900 + 40 + 7

1947 = M + CM + XL + VII

1947 = MCMXLVII

So, 1947 in Roman numerals is MCMXLVII.


Example 2. Convert 3584 to Roman numerals.

Answer:

Break down the number 3584 by place value:

  • Thousands place: 3000 = M + M + M = MMM
  • Hundreds place: 500 = D
  • Tens place: 80 = 50 + 10 + 10 + 10 = LXXX
  • Ones place: 4 = 5 - 1 = IV

Combine the Roman numerals for each component in order:

3584 = 3000 + 500 + 80 + 4

3584 = MMM + D + LXXX + IV

3584 = MMMDLXXXIV

So, 3584 in Roman numerals is MMMDLXXXIV.

Converting from Roman to Hindu-Arabic Numerals

To convert a Roman numeral to a Hindu-Arabic numeral, read the symbols from left to right. Look for pairs of symbols where a smaller value symbol is immediately followed by a larger value symbol (indicating subtraction). Calculate the value of these subtractive pairs. Then, add the values of all the symbols and combinations you've identified.

Example 1. Convert MCMLXXXVIII to Hindu-Arabic numerals.

Answer:

Examine the symbols from left to right, grouping where subtraction occurs:

  • M = 1000
  • CM = 1000 - 100 = 900 (C is smaller than M)
  • L = 50
  • XXX = 10 + 10 + 10 = 30 (Repetition, addition)
  • VIII = 5 + 1 + 1 + 1 = 8 (Addition)

Now, sum up the values of these parts:

MCMLXXXVIII = M + CM + L + XXX + VIII

MCMLXXXVIII = $1000 + 900 + 50 + 30 + 8$

MCMLXXXVIII = 2988

So, MCMLXXXVIII in Hindu-Arabic numerals is 2988.


Example 2. Convert CDXLIV to Hindu-Arabic numerals.

Answer:

Examine the symbols from left to right, grouping where subtraction occurs:

  • CD = 500 - 100 = 400 (C is smaller than D)
  • XL = 50 - 10 = 40 (X is smaller than L)
  • IV = 5 - 1 = 4 (I is smaller than V)

Now, sum up the values of these parts:

CDXLIV = CD + XL + IV

CDXLIV = $400 + 40 + 4$

CDXLIV = 444

So, CDXLIV in Hindu-Arabic numerals is 444.


Advantages and Limitations of Roman Numerals

While the Hindu-Arabic system is dominant for mathematical operations, Roman numerals still have specific uses. Understanding their strengths and weaknesses is helpful.

Advantages (in specific contexts):

Limitations (especially for mathematical applications):

The elegance and efficiency of the Hindu-Arabic place value system, particularly its ability to easily represent zero and facilitate arithmetic, are the main reasons for its global dominance in mathematics and commerce.